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Re: How to "copy" a DTD reference?

Subject: Re: How to "copy" a DTD reference?
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Wed, 13 Aug 2003 14:11:59 -0400
dtd reference
Hi Mark,

If by "DTD reference" you mean a DOCTYPE declaration's SYSTEM and/or PUBLIC identifiers, the short answer is (sadly) "no".

You can specify a string value for these identifiers in the doctype-system and doctype-public attributes on xsl:output, but they have to be string literals, they can't be copied from the input. (The parser doesn't preserve these values for the processor in any case, so there's nowhere to copy them from.)

Workarounds include using literal values (which must be known to the stylesheet in advance) and post-processing.


At 01:14 PM 8/13/2003, you wrote:
Is there a way to copy a DTD reference in the original source document using XSL?

Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
  Mulberry Technologies: A Consultancy Specializing in SGML and XML

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

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