Re: How to "copy" a DTD reference?

-thanks guys,
Mark

J.Pietschmann wrote:
>
> Not easily. You can specify a public and system id for a DTD to be
> referenced in a DOCTYPE decl in the result using xsl:output, but there
> is no way to retrieve them from the input from within the style sheet.
> You can't use the usual trick of passing the values as parameters
> either, because (AFAIK) xsl:output properties are constants. Some
> processors allow the values to be AVTs, check whether it works with
> yours.
>
> If you use the XSLT from Java (JAXP), you could try to get the
> input DTD from an entity resolver and use it to set the output
> properties of the transformer object.
>
> J.Pietschmann

Hi Mark,

If by "DTD reference" you mean a DOCTYPE declaration's SYSTEM and/or PUBLIC identifiers, the short answer is (sadly) "no".

You can specify a string value for these identifiers in the doctype-system and doctype-public attributes on xsl:output, but they have to be string literals, they can't be copied from the input. (The parser doesn't preserve these values for the processor in any case, so there's nowhere to copy them from.)

Workarounds include using literal values (which must be known to the stylesheet in advance) and post-processing.

Cheers,
Wendell