# RE: number continuation problem

 Subject: RE: number continuation problem From: "Andrew Welch" Date: Fri, 27 Jun 2003 13:17:56 +0100
```David,

Thanks for your help so far, I could use it some more as Im really stuck converting what we have to multi-level...

<root>
<if>
<node>(1)</node>
</if>
<else>
<node>(1)</node>
<node>(2)</node>
<node>(3)</node>
<node>(4)</node>
<if>
<node>(5)</node>
<node>(6)</node>
</if>
<else>
<node>(5)</node>
</else>
</else>
<if>
<node>(7)</node>
<node>(8)</node>
</if>
<else>
<node>(7)</node>
</else>
</root>

Here the point of interest is the nested <if> in the first <else>.  The numbering should follow from the parent (as in brackets).

Im working with your last post:

1 +
count(preceding-sibling::node) +
count(parent::if/preceding-sibling::if[count(node)&gt;count(following-sibling::*[1][self::else]/node)]/node) +
count(parent::else/preceding-sibling::if[position()&gt;1][count(node)&gt;count(following-sibling::*[1][self::else]/node)]/node) +
count(../preceding-sibling::else[count(node)&gt;=count(preceding-sibling::*[1][self::if]/node)]/node

Im going down the route of selecting all preceding <step>'s, then filtering the ones we don’t want, instead of counting in all the ones we do (as it works at the moment).  Is that the right approach?

I can virtually gurantee nesting only goes one deep, so I also tried adding another set of count()'s to the xpath that work on parents parents, but to no avail (and I think the preceding:: route is the preferred one).

Any further assistance would be great,

Cheers
andrew

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```

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