Re: sort

Thx in advance,
Fred.

If the depth of the sorting-element can be bounded to e.g. 3 :
First, parse your sort specification (e.g., 'person.superlogin.login') into
several variables - in this case it would give :
$sortdepth=3
$sortering1='person'
$sortering2='superlogin'
$sortering3='login'
For a simpler sort, e.g. on 'person' it would give :
$sortdepth=1
$sortering1='person'
$sortering2=''
$sortering3=''
This is easy to do with substring-before() and substring-after(), so I'll
leave it as an exercise :-)

Then you can use the following :

<xsl:apply-templates>
  <xsl:sort select="*[name()=$sortering1 and $sortdepth=1]"
order="{$direction}"/>
  <xsl:sort select="*[name()=$sortering1 and
$sortdepth=2]/*[name()=$sortering2]" order="{$direction}"/>
  <xsl:sort select="*[name()=$sortering1 and
$sortdepth=3]/*[name()=$sortering2]/*[name()=$sortering3]"
order="{$direction}"/>
</xsl:apply-templates>

Hope this helps.
--Jonathan

----- Original Message -----
From: "Frederic Leclercq" <frederic@xxxxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Saturday, February 02, 2002 1:24 AM
Subject:  sort

that's one "record" - i have 100's of them in the XML string.

Following works perfect if i would like to sort on one of the first level

tags...

<xsl:apply-templates>
 <xsl:sort select="*[name()=$sortering]" order="{$direction}"/>
</xsl:apply-templates>

But now i would like to sort the xmlstring on

"root.person.supelogin.login"

Anybody could help me out ?

Thx,
Fred.

XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list