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Re: Re: Dynamic Filter Menus

Subject: Re: Re: Dynamic Filter Menus
From: brian.witgen@xxxxxxxxxxx
Date: Fri, 26 Oct 2001 16:56:34 -0500
javascript dynamic filter

Solution one looks like the best way to go , but unfortunately Im not up to
speed on DOM. Im assuming your solution is something like using
"xsl:script" with javascript outside the templates and before I create the
indexes and then use the function in the index creation. According to
w3.org, I should be able to use "xsl:script", but the tag isnt recognised.
I must be way off. Can you pass me a little more info about the
javascript/DOM solution. Im continuing to look for info/examples but not
finding too much.

Thanks for your help.




Dimitre Novatchev <dnovatchev@xxxxxxxxx>@lists.mulberrytech.com on
10/26/2001 11:59:09 AM

Please respond to xsl-list@xxxxxxxxxxxxxxxxxxxxxx

Sent by:  owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx


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cc:

Subject:   Re: Dynamic Filter Menus


> ....and with those entries, I have created 3 keys based on the vendor,
category,
> and version:
>
> <xsl:key name="venkey" match="entry" use="@vendor" />
> <xsl:key name="catkey" match="entry" use="@category" />
> <xsl:key name="verkey" match="entry" use="@version" />
>
> The menus are a unique list of the vendors, categories, or versions to
> select. I dont have any probelm with getting the initial unique list when
> no filters have been selected yet. I am trying to make the menus work in
> such a way that when one filter is selected, the other two menus that do
> not have a filter selected will show a unique list of only those values
> that match the selected filter.
>
> Example:  With the entries above, if I choose version 2.9 as a filter,
then
> only "newmanufacturer" will show up in the vendor menu (once being
unique)
> and "gorycat2" and "gorycat3" will both show up in the category menu.
>
> I have an xml file that is updated with the selected filter for each menu
> through javascript and pulled into the template as parameters:
>
>                <xsl:call-template name="filtermenus">
>                     <xsl:with-param name="pven" select
="/docs/vendorfilter" />
>                     <xsl:with-param name="pcat" select
="/docs/categoryfilter" />
>                     <xsl:with-param name="pver" select
="/docs/versionfilter" />
>                </xsl:call-template>

One solution is (because you're passing parameters from javascript) just to
update
the definitions of the "xsl:key" -s using DOM before performing the
transformation:

 <xsl:key name="venkey" match="entry[fExp1 and fExp2 and fExp3]" use="
@vendor" />
 <xsl:key name="catkey" match="entry[fExp1 and fExp2 and fExp3]" use="
@category" />
 <xsl:key name="verkey" match="entry[fExp1 and fExp2 and fExp3]" use="
@version" />

Another solution is to construct an RTF (and convert it to a node-set)
containing
only the "entry" elements that satisfy the filters. Then use the key()
function on
this document tree. Assuming that the "entry" elements are children of the
current
node:

<xsl:variable name="vFiltered">
  <xsl:copy-of select="entry[fExp1 and fExp2 and fExp3]"/>
<xsl:variable>

<xsl:variable name="vFilteredEntries" select="xx:node-set($vFiltered)"/>

<xsl:for-each select="$vFilteredEntries">
   <xsl:variable name="uven" select="entry[generate-id()
                                       = generate-id(key('venkey',
@vendor)[1])]"/>
   <xsl:variable name="ucat" select="entry[generate-id()
                                       = generate-id(key('catkey',
@category)[1])]"/>
   <xsl:variable name="uver" select="entry[generate-id()
                                       = generate-id(key('verkey',
@version)[1])]"/>

<!--  Do whatever is necessary with the above 3 variables here -->
</xsl:for-each>

Here the "xx" prefix must be associated with the namespace in which the
vendor-supplied extension function node-set() is defined/implemented.

Hope this helped.

Cheers,
Dimitre Novatchev.




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