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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Selecting all descendants with no child nodes
Taras, Beginner XPath questions are fun. Educational for the newbies, and we all get to see what different things people come up with. At 10:24 PM 10/3/00 +0200, you wrote: .. >I'm using the XPath expression "//*[count(*)=0]" to locate all "endpoint" >nodes. > >Is there any other way to achieve this, an alternative syntax? If you mean elements with no element children (which is what your version is), then //*[not(*)] If all nodes that have no children at all (apart from attribute nodes), then //node[not(node())] but this will get you terminal (leaf) text nodes too. //*[not(node())] gets you all elements that have no text nodes, elements, comments or processing instructions inside them. They all have in common the feature that an empty node-set evaluates, in an expression that requires a boolean operand (such as a predicate []), as a boolean false; so when you do the not() operation on an empty node-set, you get boolean true. Hope that helps, Wendell ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ====================================================================== XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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