RE: Selecting all descendants with no child nodes

Since an empty nodelist evaluates to false, "//*[*]" works just as
well and should run faster. I assume you wanted a faster version (if
you had a different reason for wanting an alternative, speak up).
Yours requires some extra operations to compute than the option above.
But I suspect that performance will not matter much.

John Dreystadt

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxx]On Behalf Of Taras Tielkes
> Sent: Tuesday, October 03, 2000 4:25 PM
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: Selecting all descendants with no child nodes
>
>
> Hi,
> (I hope people don't mind a beginner xpath question now and then)
>
> I'm using the XPath expression "//*[count(*)=0]" to locate
> all "endpoint"
> nodes.
>
> Is there any other way to achieve this, an alternative syntax?
>
> Thanks in advance,
> Taras
>
>
>
>  XSL-List info and archive:
> http://www.mulberrytech.com/xsl/xsl-list
>


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