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RE: A Doubt on defineing a simpleType in xml-schema file.

xsd hexbinary
Hi Maharajan,

You should use a union type.  For example:

<xsd:simpleType name="myType">
	<xsd:union memberTypes="xsd:boolean xsd:string xsd:hexBinary"/>

Hope that helps,
Priscilla Walmsley                   priscilla@w...
Vitria Technology                     http://www.vitria.com
Author, Definitive XML Schema    (Prentice Hall, Dec. 2001)

> -----Original Message-----
> From: Mariappan, MaharajanX [mailto:m_mariappanX@t...]
> Sent: Monday, December 03, 2001 11:39 PM
> To: 'xml-dev@l...'
> Subject:  A Doubt on defineing a simpleType in 
> xml-schema file.
> Hi Folks,
> I've a question on defineing a simpleType for an attribute element in
> xml-schema.
> Value of that type may be xsd:boolean or xsd:string or xsd:hexBinary
> How can I define it?
> As per my knowledge we can derive a simpleType from one of 
> the predefined
> types[44].
> <xsd:simpleType name="myType">
> 	<xsd:choice>
> 		<xsd:restriction base="xsd:boolean"></xsd:restriction>
> 		<xsd:restriction base="xsd:string"> <xsd:length 
> value="0"/>
> </xsd:restriction>
> 		<xsd:restriction base="xsd:string"></xsd:restriction>
> 		<xsd:restriction base="xsd:hexBinary"></xsd:restriction>
> 	</xsd:choice>
> </xsd:simpleType>
> I want to define like above......but choice element cann't be within
> simpleType.
> ...........
> <xsd:attribute name="myAttribute" type="myType"/>
> .......
> Is there any way for above problem or I have to define only 
> as "xsd:string"
> which is superset type of remaining?
> TIA,
> Maharajan.
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