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Home » Boards » Stylus Studio Developer Network » XSLT Help and Discussion » Concatenate same input element values into one output element
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Nandhini ShyamSubject: Concatenate same input element values into one output element
Author: Nandhini Shyam
Date: 06 Nov 2008 05:03 PM
Originally Posted: 06 Nov 2008 04:54 PM
Hi all,

I am newbie to XSL programming.

I have this input.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<RESULTS>
<SQL10>
<RESULTSET_1>
<ROW>
<ID>ID1</ID>
<TXT>TEXT 1</TXT>
</ROW>
<ROW>
<ID>ID2</ID>
<TXT>TEXT 2</TXT>
</ROW>
<ROW>
<ID>ID1</ID>
<TXT>TEXT 3</TXT>
</ROW>
<ROW>
<ID>ID2</ID>
<TXT>TEXT 4</TXT>
</ROW>
</RESULTSET_1>
</SQL10>
</RESULTS>

And my output should be of:

<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<RESULTS>
<SQL10>
<RESULTSET_1>
<ROW>
<ID>ID1</ID>
<TXT>TEXT 1 (CR/LF - Carriage Return/Line Feed) TEXT 3</TXT>
</ROW>
<ROW>
<ID>ID2</ID>
<TXT>TEXT 2 (CR/LF - Carriage Return/Line Feed) TEXT 4</TXT>
</ROW>
</RESULTSET_1>
</SQL10>
</RESULTS>

All the same IDs should have its TXT values grouped together, separated by (CR/LF - Carriage Return/Line Feed)

From my newbie XSL knowledge

I started doing this:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
<RESULTS>
<SQL10>
<RESULTSET_1>
<xsl:for-each select="//ROW">
<ROW>
<ID><xsl:value-of select="ID"/></ID>
<TXT>
<xsl:for-each select="TXT">
<xsl:choose>
<xsl:when test=". and string-length(normalize-space(.))=0">
<xsl:value-of select="'.'"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</TXT>
</ROW>
</xsl:for-each>
</RESULTSET_1>
</SQL10>
</RESULTS>
</xsl:template>
</xsl:stylesheet>

Ofcourse its not working as expected.

Can you please help me out. Many thanks !!
Postnext
James DurningSubject: Concatenate same input element values into one output element
Author: James Durning
Date: 07 Nov 2008 03:24 PM
Originally Posted: 07 Nov 2008 03:23 PM
The best way is probably Muenchian grouping:
http://www.jenitennison.com/xslt/grouping/muenchian.html

Change this from:
<xsl:for-each select="//ROW">
to:
<xsl:for-each select="//ROW[not(preceding::ROW[ID = current()/ID])]">

Then when getting the values you would get all rows with the same ID.
<xsl:for-each select="//ROW[ID = current()/ID]">
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Nandhini ShyamSubject: Concatenate same input element values into one output element
Author: Nandhini Shyam
Date: 07 Nov 2008 04:32 PM
Thanks...

working that way now :-)
 
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