XML Editor
Sign up for a WebBoard account Sign Up Keyword Search Search More Options... Options
Chat Rooms Chat Help Help News News Log in to WebBoard Log in Not Logged in
Show tree view Topic
Topic Page 1 2 3 4 5 6 7 8 9 Go to previous topicPrev TopicGo to next topicNext Topic
James DurningSubject: Indexing by group?
Author: James Durning
Date: 12 Nov 2004 02:10 PM
I've got a structure like
<link parent="1" target="3"/>
<link parent="1" target="4"/>
<link parent="1" target="5"/>
<link parent="2" target="6"/>
<link parent="2" target="7"/>
<link parent="3" target="8"/>
<link parent="1" target="9"/>
The final simplified structure looks like:
<link parent="1" order="1" target="3"/>
<link parent="1" order="2" target="4"/>
<link parent="1" order="3" target="5"/>
<link parent="2" order="1" target="6"/>
<link parent="2" order="2" target="7"/>
<link parent="3" order="1" target="8"/>
<link parent="1" order="1" target="9"/>
However, I am missing the last link (parent=1, target=9)
I need other to be the index based on the parent. what I have now uses the Muenchian method and then uses the position() to get the order. The actual 'links' contain much more information, and involve copying complex nodes..

<xsl:key name="linkbyparent" match="link" use="@parent" />
<xsl:variable name="merged">
<xsl:for-each select="*\link[count(. | key('linkbyparent', @parent)[1]) = 1]">
<xsl:for-each select="key('linkbyparent', @parent)">
<xsl:copy-of "@*"/>
<xsl:attribute name="order"><xsl:value-of select="position()"/></xsl:attribute>

<xsl:for-each select="*\link[count(. | key('linkbyparent', @parent)[1]) = 1]">
seems to be the problem line.. anyone know a different method, or one that doesn't use key?

Ivan PedruzziSubject: Indexing by group?
Author: Ivan Pedruzzi
Date: 14 Nov 2004 10:01 PM
Hi James,

If I have understood what you are trying to do the following
should help

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="linkbyparent" match="link" use="concat(@parent, local-name(..) )"/>
<xsl:template match="/">
<xsl:for-each select="*/*/link[count(. | key('linkbyparent', concat(@parent, local-name(..) ) )[1]) = 1]">
<xsl:for-each select="key('linkbyparent', concat(@parent, local-name(..) ) )">
<xsl:copy-of select="@*"/>
<xsl:attribute name="order">
<xsl:value-of select="position()"/>


Topic Page 1 2 3 4 5 6 7 8 9 Go to previous topicPrev TopicGo to next topicNext Topic
Download A Free Trial of Stylus Studio 6 XML Professional Edition Today! Powered by Stylus Studio, the world's leading XML IDE for XML, XSLT, XQuery, XML Schema, DTD, XPath, WSDL, XHTML, SQL/XML, and XML Mapping!  

Log In Options

Site Map | Privacy Policy | Terms of Use | Trademarks
Stylus Scoop XML Newsletter:
W3C Member
Stylus Studio® and DataDirect XQuery ™are from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2016 All Rights Reserved.