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sol dgnSubject: Xpath of each element
Author: sol dgn
Date: 01 Jul 2011 08:37 AM
Hello All.

I want to extract XPATH of all xml elemememts in any xml file.

Is there any way to get it?

I know name() function but it just give me current node value. I need xpath of element.

Thanks.
Postnext
Ivan PedruzziSubject: Xpath of each element
Author: Ivan Pedruzzi
Date: 20 Jul 2011 03:59 PM

This sounds like a navigation exercise


<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>

<xsl:template match="*">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="concat('/', local-name(.))"/>
</xsl:for-each>
<xsl:value-of select="'&#xA;'"/>

<xsl:for-each select="@*">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="concat('/', local-name(.))"/>
</xsl:for-each>
<xsl:value-of select="concat('/@', local-name(.))"/>
<xsl:value-of select="'&#xA;'"/>
</xsl:for-each>
<xsl:apply-templates select="*"/>
</xsl:template>

<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>

</xsl:stylesheet>

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sol dgnSubject: Xpath of each element
Author: sol dgn
Date: 11 Aug 2011 07:23 AM
Thanks.

I had also received few other reply. I am pasting link to another thread.

http://www.ibm.com/developerworks/forums/thread.jspa?threadID=364457&tstart=0
   
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