XML Editor
Sign up for a WebBoard account Sign Up Keyword Search Search More Options... Options
search
Chat Rooms Chat Help Help News News Log in to WebBoard Log in Not Logged in
Home » Boards » Stylus Studio Developer Network » XSLT Help and Discussion » XSLT to sort a list alphabetically and divide it into two columns...
Conferences Close Tree View
+ Stylus Studio Feature Requests (1192)
+ Stylus Studio Technical Forum (14621)
+ Website Feedback (249)
- XSLT Help and Discussion (7625)
-> + Use of before and after string (3) Sticky Topic
-> - How do I substitute element ty... (1)
-> + How does one add working days ... (4)
-> - Help, I have existing XLT and... (1)
-> + Need help on XSLT issue - (2)
-> + EDI to XML Conversion (7)
-> - XML To JSON Conversion using X... (1)
-> + Formatting Paragraphs to same ... (2)
-> - Grouping of records (1)
-> + Problems with xsd 1.1 (4)
-> + XML to HL7 mapping (3)
-> + XSLT 3 and Iterate (2)
-> + XSL-FO to PDF preview (3)
-> + java.lang.RuntimeException: Er... (2)
-> + Create Acroforms with Stylus X... (2)
-> + How to change XSLT parameter s... (3)
-> + how to change format of the da... (2)
-> + Search "Next 8 Results " doesn... (2)
-> - Support for Git (1)
-> + newbee (8)
-- [1-20] [21-40] [41-60] Next
+ XQuery Help and Discussion (2017)
+ Stylus Studio FAQs (159)
+ Stylus Studio Code Samples & Utilities (364)
+ Stylus Studio Announcements (113)
Topic  
Postnext
ena jenkinsSubject: XSLT to sort a list alphabetically and divide it into two columns...
Author: ena jenkins
Date: 11 Mar 2009 06:39 PM
Originally Posted: 11 Mar 2009 06:40 PM
Hi,

I need to sort a list of countries alphabetically and display the list
in two columns, but I need the alphabetical list to read vertically
instead of left to right. How do I do this?

Type of output needed (Example):

Australia Finland
Belgium Hong Kong
Canada India
Chile Switzerland



Here is the XML (modified):


<countries>


<country>
<name>Hong Kong</name>
<url>/international/funding/countries/hongkong.aspx</url>
</country>


<country>
<name>Finland</name>
<url>/international/funding/countries/finland.aspx</url>
</country>


<country>
<name>Colombia</name>
<url>/international/funding/countries/colombia.aspx</url>
</country>


<country>
<name>Belgium</name>
<url>/international/funding/countries/belgium</url>
</country>


<country>
<name>China</name>
<url>/international/funding/countries/china.aspx</url>
</country>


<country>
<name>India</name>
<url>/international/funding/countries/india.aspx</url>
</country>


<country>
<name>Australia and New Zealand</name>
<url>/international/funding/countries/australia.aspx</url>
</country>


<country>
<name>Switzerland</name>
<url>/international/funding/countries/switzerland.aspx</url>
</country>


</countries>


Here is my XSLT:


<xsl:for-each select="countries/country">
<xsl:sort select="name"/>
<p>
<a>
<xsl:attribute name="href">
<xsl:value-of select="url"/>
</xsl:attribute>
<xsl:value-of select="name"/>
</a>
</p>


</xsl:for-each>


Thanks...
Any help would be greatly appreciated!

Postnext
ena jenkinsSubject: XSLT to sort a list alphabetically and divide it into two columns...
Author: ena jenkins
Date: 11 Mar 2009 06:44 PM
Australia ____________ Finland
Belgium ______________ Hong Kong
Canada _______________ India
Chile ________________ Switzerland


**My spaces (tabs) used to indicate columns got stripped out when I submitted, but you get the point...
Postnext
John BamptonSubject: XSLT to sort a list alphabetically and divide it into two columns...
Author: John Bampton
Date: 12 Mar 2009 10:31 AM
Originally Posted: 12 Mar 2009 10:29 AM
Hi this should do the trick

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="xs"
version="2.0">
<xsl:output method="xml" indent="yes"></xsl:output>
<xsl:template match="/">
<xsl:variable name="sortedcountries">
<countries>
<xsl:for-each select="countries/country">
<xsl:sort select="name"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</countries>
</xsl:variable>
<xsl:variable name="counthalf" select="count(countries/country) div 2"></xsl:variable>
<table>
<xsl:for-each select="$sortedcountries/countries/country">

<xsl:if test="position() &lt;= $counthalf">
<tr>
<td>
<a href="{url}"><xsl:value-of select="name"/></a>
</td>
<td>
<a href="{./following-sibling::country[position() = 4]/url}"><xsl:value-of select="./following-sibling::country[position() = 4]/name"/></a>
</td>
</tr>
</xsl:if>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>

Thanks, John Bampton
Posttop
James DurningSubject: XSLT to sort a list alphabetically and divide it into two columns...
Author: James Durning
Date: 12 Mar 2009 03:12 PM
Originally Posted: 12 Mar 2009 02:21 PM
Replace the 4's with $counthalf, and change variable declaration to:
<xsl:variable name="counthalf" select="ceiling(count(countries/country) div 2)"/>

to deal with odd numbers.

There's no need to create an extra variable to hold the sorted countries; the position() function automatically updates when using the for-each and sort elements.


With these modifications, you would only need XSLT 1.0.
   
Download A Free Trial of Stylus Studio 6 XML Professional Edition Today! Powered by Stylus Studio, the world's leading XML IDE for XML, XSLT, XQuery, XML Schema, DTD, XPath, WSDL, XHTML, SQL/XML, and XML Mapping!  
go

Log In Options

Site Map | Privacy Policy | Terms of Use | Trademarks
Stylus Scoop XML Newsletter:
W3C Member
Stylus Studio® and DataDirect XQuery ™are from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2016 All Rights Reserved.