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Brad MooreSubject: Transforming XML to XML - grouping
Author: Brad Moore
Date: 29 Nov 2007 12:40 PM
I've been working on this for two days and have now successfully pulled out all my hair... I could use some help.... I am building an Access database that needs to export personnel scheduling information to XML, so it can be imported into another program. I know Access, however, much to my frustration, don't know XML. My output format looks like this....

<qry_DAR_Export>
<LOCATION>6C00: Haldimand County</LOCATION>
<PLATOON>Admin</PLATOON>
<USER_NAME>SMITH, P.G. (Paul)</USER_NAME>
<BADGE_EMP_NO>1234</BADGE_EMP_NO>
<ROSTER_DUTY_CODE>OIC</ROSTER_DUTY_CODE>
<USER_PROFILE_ID>6789</USER_PROFILE_ID>
<YEAR>2008</YEAR>
<SHIFT_x0020_DATE>04/01/08</SHIFT_x0020_DATE>
<ON_DUTY>0815</ON_DUTY>
<OFF_DUTY>1630</OFF_DUTY>
</qry_DAR_Export>
<qry_DAR_Export>
<LOCATION>6C00: Haldimand County</LOCATION>
<PLATOON>Admin</PLATOON>
<USER_NAME>SMITH, P.G. (Paul)</USER_NAME>
<BADGE_EMP_NO>1234</BADGE_EMP_NO>
<ROSTER_DUTY_CODE>OIC</ROSTER_DUTY_CODE>
<USER_PROFILE_ID>6789</USER_PROFILE_ID>
<YEAR>2008</YEAR>
<SHIFT_x0020_DATE>05/01/08</SHIFT_x0020_DATE>
<ABSENCE_REASON_CODE>R</ABSENCE_REASON_CODE>
<ON_DUTY />
<OFF_DUTY />
</qry_DAR_Export>

With one entry for each day of the year. I need to transform it into XML that looks like this....

<USER PLATOON="*Admin*" USER_NAME="*SMITH, P.G. (Paul)*" BADGE_EMP_NO="*1234*" ROSTER_DUTY_CODE="*OIC*" USER_PROFILE_ID="*6789*">
<SCHEDULE>
<SHIFT DATE="*10/11/07*" ABSENCE_REASON_CODE="*R*" ON_DUTY="" OFF_DUTY="" />
<SHIFT DATE="*11/11/07*" ABSENCE_REASON_CODE="*R*" ON_DUTY="" OFF_DUTY="" />
<SHIFT DATE="*12/11/07*" ABSENCE_REASON_CODE="*ST*" ON_DUTY="" OFF_DUTY="" />
<SHIFT DATE="*13/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*14/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*15/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*16/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*17/11/07*" ABSENCE_REASON_CODE="*R*" ON_DUTY="" OFF_DUTY="" />
<SHIFT DATE="*18/11/07*" ABSENCE_REASON_CODE="*R*" ON_DUTY="" OFF_DUTY="" />
<SHIFT DATE="*19/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*20/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*21/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*22/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
<SHIFT DATE="*23/11/07*" ABSENCE_REASON_CODE="" ON_DUTY="*0800*" OFF_DUTY="*1600*" />
.
.
.
</SCHEDULE>
</USER>

etc..... Again with one <SHIFT> entry for each day of the year and one <USER> entry for each employee. I can get the transformation to look this way when I export one user from the database, but when I have more than one user, I can't get it to start a new <USER> at the end of the year (i.e - <SHIFT DATE="31/12/07"... for user "SMITH" is immediately followed by <SHIFT DATE="01/01/07".... for user "JONES" with no <USER> tag)....

This is the XSL I have generated with Stylus Studio

<?xml version='1.0' ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:a="http://jus00aas0890/DARReporting/content/admin/roster/RosterSchema.xml">
<xsl:template match="/">
<ROSTER xmlns="http://jus00aas0890/DARReporting/content/admin/roster/RosterSchema.xml">
<xsl:attribute name="LOCATION">
<xsl:value-of select="dataroot/qry_DAR_Export/LOCATION"/>
</xsl:attribute>
<USER>
<xsl:attribute name="PLATOON">
<xsl:value-of select="dataroot/qry_DAR_Export/PLATOON"/>
</xsl:attribute>
<xsl:attribute name="USER_NAME">
<xsl:value-of select="dataroot/qry_DAR_Export/USER_NAME"/>
</xsl:attribute>
<xsl:attribute name="BADGE_EMP_NO">
<xsl:value-of select="dataroot/qry_DAR_Export/BADGE_EMP_NO"/>
</xsl:attribute>
<xsl:attribute name="ROSTER_DUTY_CODE">
<xsl:value-of select="dataroot/qry_DAR_Export/ROSTER_DUTY_CODE"/>
</xsl:attribute>
<xsl:attribute name="USER_PROFILE_ID">
<xsl:value-of select="dataroot/qry_DAR_Export/USER_PROFILE_ID"/>
</xsl:attribute>
<SCHEDULE>
<xsl:for-each select="dataroot/qry_DAR_Export">
<SHIFT>
<xsl:attribute name="DATE">
<xsl:value-of select="SHIFT_x0020_DATE"/>
</xsl:attribute>
<xsl:attribute name="ABSENCE_REASON_CODE">
<xsl:value-of select="ABSENCE_REASON_CODE"/>
</xsl:attribute>
<xsl:attribute name="ON_DUTY">
<xsl:value-of select="ON_DUTY"/>
</xsl:attribute>
<xsl:attribute name="OFF_DUTY">
<xsl:value-of select="OFF_DUTY"/>
</xsl:attribute>
</SHIFT>
</xsl:for-each>
</SCHEDULE>
</USER>
</ROSTER>
</xsl:template>
</xsl:stylesheet>

Any suggestions? I have search the list archives and with every keyword I can think of on the web, to no avail.......
Thanks,
Brad
Posttop
(Deleted User) Subject: Transforming XML to XML - grouping
Author: (Deleted User)
Date: 30 Nov 2007 05:15 AM
Hi Brad,
you need to place the code between <USER> and </USER> inside a loop, that is executed once for every user you have in the exported data.
Have a look at the grouping technique described at http://www.jenitennison.com/xslt/grouping/muenchian.html to see how this can be done.

Hope this helps,
Alberto

   
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