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chris wallaceSubject: Path problem
Author: chris wallace
Date: 21 Feb 2006 06:31 AM
With this input:
<doc>
<bs>
<b><c>A</c><d>AAA</d></b>
<b><c>B</c><d>BBB</d></b>
<b><c>C</c><d>CCC</d></b>
<b><c>D</c><d>DDD</d></b>
</bs>
<body>
<x>A</x>
<x>D</x>
</body>
</doc>

I want to expand the codes (A, D) to their values in the bs table. (AAA, DDD)

This template works:
<xsl:template match="x">
<xsl:variable name="x">
<xsl:value-of select="."/>
</xsl:variable>
<xsl:value-of select="/doc/bs/b[c=$x]/d)"/>
</xsl:template>

But this does not:
<xsl:template match="x">
<xsl:value-of select="/doc/bs/b[c=.]/d)"/>
</xsl:template>

and I dont understand why. I would welcome enlightenment.

Chris
Postnext
(Deleted User) Subject: Path problem
Author: (Deleted User)
Date: 21 Feb 2006 10:52 AM

Hi, Chris. When you create a predicate inside brackets ( b[c=$x], for example), you are setting a new input context set to the current node being examined by the predicate. The variable you set in your first XSLT sample is what allows you to compare a node with the input context of the template.

The reason your second XSLT doesn't work is that when the evaluation reaches the predicate ( b[c=.] ), the context node points to a "b" node. In order to reach the "x" node, you either need to use the current() function (like [c=current()], for example), or store the value of "." as a variable and use it later (as you did in your first XSLT).

Hope this helps.

David Foster
Stylus Studio Team
Posttop
chris wallaceSubject: Path problem
Author: chris wallace
Date: 21 Feb 2006 11:48 AM
Hi David

Thank you very much for that answer - just the ticket! And of course thats just why you need current()!

Chris
   
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