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Anant BadgujarSubject: How to Pass parameter to Xsl:Include href and assign parameter to href
Author: Anant Badgujar
Date: 04 Jun 2007 07:13 AM
Originally Posted: 04 Jun 2007 06:59 AM
I want to pass a parameter value to xsl:include href . This parameter value is a relative path picked up from the config file using C#.

The included file has some common functions which are used across multiple XSLT files.

This path is programmatically passed using the argument list for the xsl transform method.

Is there any other other way that I can include this file on runtime?

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(Deleted User) Subject: How to Pass parameter to Xsl:Include href and assign parameter to href
Author: (Deleted User)
Date: 04 Jun 2007 03:21 PM
Hi,
the xsl:include can only have a literal URI as location value; being evaluated at compile time, no variable or parameter can be used to change it dinamically.

Alberto

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Ivan PedruzziSubject: How to Pass parameter to Xsl:Include href and assign parameter to href
Author: Ivan Pedruzzi
Date: 04 Jun 2007 11:51 PM

Hi Anant,

The following code shows how to change your XSLT programmatically using a meta stylesheet


// Change XSLT programmatically
XmlReader xmlReader = XmlReader.Create("c:\\Temp\\MainInclude.xsl");
StringBuilder sb = new StringBuilder();
XmlWriter xmlWriter = XmlWriter.Create(sb);
XslCompiledTransform xslt = new XslCompiledTransform();
xslt.Load("c:\\Temp\\fixXSLInclude.xsl");
XsltArgumentList xsltArgs = new XsltArgumentList();
xsltArgs.AddParam("href", "", "c:\\temp\\myCommonInclude.xsl");
xslt.Transform(xmlReader, xsltArgs, xmlWriter);

// Run the modified stylesheet
XmlReader xslReader = XmlReader.Create(new StringReader(sb.ToString()));
xslt.Load(xslReader);
xmlReader = XmlReader.Create("c:\\Temp\\books.xml");
xmlWriter = XmlWriter.Create(Console.Out);
xslt.Transform(xmlReader, xmlWriter);



------------ fixXSLInclude.xsl

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="href"/>

<xsl:template match="*">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="xsl:include">
<xsl:copy>
<xsl:attribute name="href">
<xsl:value-of select="$href"/>
</xsl:attribute>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>


Hope this helps
Ivan Pedruzzi
Stylus Studio Team

 
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