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steven matthews

Subject: Opening and reading files
Author: steven matthews
Date: 01 Apr 2007 03:19 PM

Q1: how do you open a file in XSLT and display the contents ? I am using this code but it only displays the URI (path) of the file stored in <text>


<xsl:if test="starts-with($MM_TEXT, 'C:\')">
<p><xsl:value-of select="text"/></p>
</xsl:if>

Is this possible in XSLT ?

Do you have any suggestions ?

Thanks,

Steven

Ivan Pedruzzi

Subject: Opening and reading files
Author: Ivan Pedruzzi
Date: 01 Apr 2007 11:36 PM

Hi Steven

What kind of file you are trying to open?

If it's an XML file you copy the entire document in the result tree with the following
<xsl:copy-of select="document($MM_TEXT)"/>

If it's CSV, TAB or EDI you may use the DataDirect XML Converter URIRsolver

CSV example
<xsl:copy-of select="document(adapter:CSV?$MM_TEXT)"/>

If it is a free text you could switch to XSLT 2.0 and use unparsed-text
http://www.w3.org/TR/xslt20/#unparsed-text

Ivan Pedruzzi
Stylus Studio Team
http://www.stylusstudio.com/xml_download.html

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