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Victoria Lu

Subject: Help for preceding-sibling in XSLT
Author: Victoria Lu
Date: 31 Oct 2006 11:51 AM

I have a xml data as A section below. I want to detect IC/@TYPE = '6f'|'ks' immediately preceding a <SB> but not <BF>. I wrote a .xsl as B section below. but result always show both '6f' and 'ks' before 'Sheraton.'.
How do I get rid of '6f' that is preceding a <BF> not <SB>?

(Attached a file "GOLD2008.dtd")

Thank you so much,
Victoria

---------A section-----------
<?xml version="1.0"?>
<!DOCTYPE CHAPTER SYSTEM "GOLD2008.dtd"
[

<!ENTITY del "">

<!ENTITY n "">
<!ENTITY ne "">
<!ENTITY slash "/">
]>
<CHAPTER><PARSE.ISBN TAG="1-4000-1682-7" /><INTRO><SEQ>40</SEQ>

<H TYPE="2">

<HEAD>Lucaya</HEAD>

<R PROPNUM="50798">

<IC TYPE="6f"/><IC TYPE="f2"/><BF>Our Lucaya Beach & Golf Resort.</BF> Grand Bahama's grandest resort.[]

<IC TYPE="ks"/><SB>Sheraton.</SB> Geared toward family vacationers.[]

<SB>Westin Breakers Cay.</SB>.[]

<SB>Westin Lighthouse Pointe.</SB> Two-story structures.[]
</R>

</H>

</CHAPTER>

---------B section-----------

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>

<xsl:template match="/">
<html>
....
<body style="text-align: center">
<xsl:apply-templates select="CHAPTER/H/R"/>
</body>
</html>
</xsl:template>

<xsl:template match="CHAPTER/H/R">
<table width="100%" border="1">
<tbody>
<xsl:for-each select=".">
<xsl:if test="SB[preceding-sibling::*[1][self::IC]]|SB[preceding-sibling::*[1][self::BLT]]">
<tr style="background-color: bisque">
<td width="50%">
<xsl:for-each select="IC">
<xsl:choose>
<xsl:when test="IC[following-sibling::*[1][self::BF]]">
<li value="0">
<xsl:text> No IC/@TYPE before BF</xsl:text>
</li>
</xsl:when>
<xsl:when test="@TYPE eq'6f'">
<li value="0">
<xsl:value-of select="@TYPE"/>
</li>
</xsl:when>
<xsl:when test="@TYPE eq 'ks'">
<li value="0">
<xsl:value-of select="@TYPE"/>
</li>
</xsl:when>
<xsl:otherwise>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</td>
<td width="50%">
<xsl:value-of select="SB[1]"/>
</td>
</tr>
</xsl:if>
</xsl:for-each>
</tbody>
</table>
</xsl:template>

</xsl:stylesheet>

gold2008.dtd
for xml file

James Durning

Subject: Help for preceding-sibling in XSLT
Author: James Durning
Date: 31 Oct 2006 03:03 PM

Change <xsl:when test="IC[following-sibling::*[1][self::BF]]">
to
<xsl:when test="following-sibling::BF and (following-sibling::*[name()='BF' or name()='SB'])[1]/name() = 'BF' ">
FILTER THIS NODE OUT
</xsl:when>

If this node has a following BF sibling, and the next BF or SB sibling it has is a BF one, then filter it out. This is only possible in XSLT 2.0, which you are using.

Victoria Lu

Subject: Help for preceding-sibling in XSLT
Author: Victoria Lu
Date: 31 Oct 2006 03:15 PM

It's so cool! You saved my life!
Now, I'm wondering what to do if using XSLT 1.0

James Durning

Subject: Help for preceding-sibling in XSLT
Author: James Durning
Date: 01 Nov 2006 11:42 AM

In 1.0, due to the name() function, the syntax is a little different.
<xsl:when test="name((following-sibling::*[name()='BF' or name()='SB'])[1]) = 'BF'"/>

This actually works for both 1.0 and 2.0; was just unable to remember the exact syntax trick yesterday.

On further thought, you don't even need to initially test for following-sibling::BF, since if there are no following siblings, the test will simply return ('' =? 'BF') = false.

Victoria Lu

Subject: Help for preceding-sibling in XSLT
Author: Victoria Lu
Date: 01 Nov 2006 11:50 AM

Can't believe you relyed to me again.
It's even cooler! Thank you expert!

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