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giancarlo rossi

Subject: build parameter as string
Author: giancarlo rossi
Date: 23 Oct 2006 05:24 AM
Originally Posted: 22 Oct 2006 05:56 PM

I need to build a parameter depending on a xsl:param

<xsl:param name="supplier_param" />

<xsl:variable name="test">
<xsl:choose>
<xsl:when test="$supplier_param">
Complete='true' and Supplier='<xsl:value-of select="$supplier_param" />'
</xsl:when>
<xsl:otherwise>
Complete='true'
</xsl:otherwise>
</xsl:choose>
</xsl:variable>

<--then i pass the string as a parameter -->

<xsl:for-each select="/root[$test]/mynode">
'mycode
</xsl:for each>

but the for-each filter is not applyed.

I tryed also with:

<xsl:for-each select="/root[string($test)]/mynode">
'mycode
</xsl:for each>

with the same results.

Ivan Pedruzzi

Subject: build parameter as string
Author: Ivan Pedruzzi
Date: 23 Oct 2006 10:13 AM

XSLT does not allow to create XPath expressions dynamically.

Use the following instead

<xsl:for-each select="/root[Complete='true' and (Supplier = $supplier_param or not($supplier_param))]/mynode">

If "Complete" and "Supplier" are attributes use the prefix @
@Complete='true'

Ivan Pedruzzi
Stylus Studio Team

Tony Lavinio

Subject: build parameter as string
Author: Tony Lavinio
Date: 23 Oct 2006 10:14 AM

You can't do that.
XPaths are resolved at compile time, not run-time.
Variables are not substitution macros.

Instead of <xsl:for-each...> you might want to do pass the
kind of condition in a parameter, and then have something
like this:

<xsl:choose>
<xsl:when test="$supplier_param = ''">
<xsl:apply-templates select="/root[Complete='true']/mynode"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="/root[Complete='true' and and Supplier=$supplier_param]/mynode"/>
</xsl:otherwise>
</xsl:choose>

and then have a template

<xsl:template match="mynode">
'mycode
</xsl:template>

Generally, when you use a for-each, you are not thinking
in the 'XSLT way'. Examine carefully how templates are
used, and you will probably find your code shrinking.

giancarlo rossi

Subject: build parameter as string
Author: giancarlo rossi
Date: 25 Oct 2006 09:21 AM
Originally Posted: 25 Oct 2006 09:20 AM

Thanks guy,
it works and I understand better the template logic.

Bu I need to try to implement your code:

right now I Have this:

<xsl:for-each select="msxsl:node-set($base)/item[(supplier = $supplier_param or not($supplier_param))]">

<xsl:for-each>

this case filter just one parameter but if I have an array for example:

<xsl:param name="supplier_param" select="Alitalia,easyjet" />

this xpath expression
(msxsl:node-set($base)/item[(supplier = $supplier_param or not($supplier_param))] )

obviulsy not found results.

So the questions is:
Is possible in xsl filter by an array param ?
Thanks in advance

Tony Lavinio

Subject: build parameter as string
Author: Tony Lavinio
Date: 25 Oct 2006 02:39 PM

This is probably not the best way to do this, but not seeing
the rest of your code we can only guess.

... base)/item[contains($supplier_param, supplier)] ...

http://www.w3.org/TR/xpath#function-contains

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