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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: compare two nodes (the child elements, not the str Play the video Subject: Re: compare two nodes (the child elements, not the string values) in XSLT 1.0 From: Wolfhart Totschnig <wolfhart@xxxxxxxxxxxxx> Date: Wed, 06 Jul 2011 15:40:27 -0500 How about this (not very cool): test="concat(path/person/first, '|', path/person/first, '|', path/person/first) = concat(first, '|', middle, '|', last) This does not work. The concat() function transforms the node sets into strings, and so the expression "concat(path/person/first, '|', path/person/middle, '|', path/person/last)" takes the values of the <first>, <middle>, and <last> elements of the *first* <person> element (the string value of a node set is by definition the string value of the first node in the node set) and concatenates them. So the test you propose will always yield "false" unless the context node happens to be equal to the first <person> element. Wolfhart Current Thread RE: compare two nodes (the child elements, not the string values) in XSLT 1.0, (continued) Robby Pelssers - 6 Jul 2011 18:57:37 -0000 Robby Pelssers - 6 Jul 2011 18:58:28 -0000 Wolfhart Totschnig - 6 Jul 2011 19:15:56 -0000 Michael Müller-Hillebrand - 6 Jul 2011 20:22:38 -0000 Wolfhart Totschnig - 6 Jul 2011 20:41:04 -0000 <= Wendell Piez - 6 Jul 2011 20:45:42 -0000 Wolfhart Totschnig - 7 Jul 2011 04:55:52 -0000 Michel Hendriksen - 7 Jul 2011 08:34:33 -0000 Wendell Piez - 7 Jul 2011 16:03:09 -0000 <- Previous Index Next -> Re: compare two nodes (the ch, Michael Müller-Hille Thread Re: compare two nodes (the ch, Wendell Piez Re: compare two nodes (the ch, Michael Müller-Hille Date Re: compare two nodes (the ch, Wendell Piez Month

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