Re: compare two nodes (the child elements, not the str
Am 06.07.2011 um 20:54 schrieb Wolfhart Totschnig: > I have a seemingly simple xslt problem to which I cannot find the solution. I want to test whether the context node, which is an <author> element with the form (first?, middle?, last), is equal to one of a set of <person> elements. By "equal" I mean having the same child elements and values of these elements. At first, I thought it would be as easy as > > test="path/person = ." > > But then I realized that the "=" operator compares the string values of the nodes Wolfhart, How about this (not very cool): test="concat(path/person/first, '|', path/person/first, '|', path/person/first) = concat(first, '|', middle, '|', last)" - Michael M|ller-Hillebrand
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