Here is a different algorithm, than Mike

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                       version="2.0">

  <xsl:output method="text" />

  <xsl:template match="Orders">
    <xsl:for-each-group select="*" group-starting-with="StartOrderGroup">
      <xsl:text>&#xa;Order&#xa;</xsl:text>
      <xsl:text>-----&#xa;</xsl:text>
      <xsl:variable name="curr-group" select="current-group()" />
      <xsl:variable name="indx" select="index-of(for $x in $curr-group
return $x/local-name(), 'EndOrderGroup')" />
      <xsl:for-each select="$curr-group[position() &gt; 1 and
position() &lt; $indx]">
        <xsl:value-of select="local-name()" /> - <xsl:value-of
select="Id" /><xsl:text>&#xa;</xsl:text>
      </xsl:for-each>
    </xsl:for-each-group>
  </xsl:template>

</xsl:stylesheet>


On Mon, Dec 22, 2008 at 4:07 PM, Fredde Hedberg <syte_orion@xxxxxxxxx> wrote:
>> The problem is solvable with XSLT, provided your input XML
>> is well
>> formed. But your input is not a valid XML document.
>>
>> for e.g., <Id=1/> is not a valid XML fragment, and
>> XML parser
>> complains about it.
>
> My mistake, I apologize. When I simplified my XML I made it more bad formed than it really is...
>
> <Orders>
>  <StartOrderGroup>
>    <Id>1</Id>
>  </StartOrderGroup>
>  <Car>
>    <Id>2</Id>
>  </Car>
>  <Car>
>    <Id>3</Id>
>  </Car>
>  <Bus>
>    <Id>4</Id>
>  </Bus>
>  <EndOrderGroup>
>    <Id>5</Id>
>  </EndOrderGroup>
>  <Car>
>    <Id>6</Id>
>  </Car>
>  <Truck>
>    <Id>7</Id>
>  </Truck>
>  <StartOrderGroup>
>    <Id>8</Id>
>  </StartOrderGroup>
>  <Truck>
>    <Id>9</Id>
>  </Truck>
>  <EndOrderGroup>
>    <Id>10</Id>
>  </EndOrderGroup>
> </Orders>
>
> That's at least valid XML :)
> You've given me hope by saying it is solvable. Will this new XML-fragment allow you to show me how? That would basically save christmas for me...
>
> Regards
>
> Fredde



-- 
Regards,
Mukul Gandhi