Re: Format Number and Empy Elements

Hi Guys

I still have a few problems with this. Here's my sample XML

<numbers>
	<number>
		<id>A</id>
		<value></value>
	</number>
	<number>
		<id>B</id>
		<value>0</value>
	</number>
	<number>
		<id>C</id>
		<value>1000</value>
	</number>
	<number>
		<id>D</id>
		<value>-100</value>
	</number>
	<number>
		<id>E</id>
		<value>99.99</value>
	</number>
</numbers>

RESULTS

concat('0', value) works brilliantly, except when there are negative
numbers (as I get '0-100'). There's always a catch

Strangely, sum(value[.]) still gave NaN for Element A



Here's my XSL

<!-- concat('0',value)-->
<table>
	<xsl:for-each select="number">
		<tr>
			<td><xsl:value-of select="id"/></td>
			<td align="right"><xsl:value-of
select="format-number(number(concat('0', value)), '#,.00')"/></td>
		</tr>
	</xsl:for-each>
</table>

<!-- sum(value[.])-->
<table>
	<xsl:for-each select="number">
		<tr>
			<td><xsl:value-of select="id"/></td>
			<td align="right"><xsl:value-of
select="sum(value[.])"/></td>
		</tr>
	</xsl:for-each>
</table>

Forgot to mention, I'm stuck with XSLT 1.0 (bit I guess you figured that
out)