RE: Duplicate Nodes in XSL and transform them

I see what you mean, but I guess the case I gave was a little too
simple. What I really want to do is take any nodeset and copy it n times
and replace a string in each copy. Like this:

Input:

<anything>
  <innerAnyThing>
    <anyValue>replaceMe</ anyValue >
  </ innerAnyThing >
  <innerAnyThing>
	<another>
    		<anyValue>replaceMe</ anyValue >
	</another>
  </ innerAnyThing >
  <innerAnyThing>
    <anyValue>replaceMe</ anyValue >
  </ innerAnyThing >
</anything>


Assuming input is 3 iterations the output of last one would be:

<anything>
  <innerAnyThing>
    <anyValue>replaced1</ anyValue >
  </ innerAnyThing >
  <innerAnyThing>
	<another>
	    <anyValue> replaced1</ anyValue >
	</another>
  </ innerAnyThing >
  <innerAnyThing>
    <anyValue> replaced1</ anyValue >
  </ innerAnyThing >
</anything>

<anything>
  <innerAnyThing>
    <anyValue>replaced2</ anyValue >
  </ innerAnyThing >
  <innerAnyThing>
	<another>
	    <anyValue> replaced2</ anyValue >
	</another>
  </ innerAnyThing >
   <innerAnyThing>
    <anyValue> replaced2</ anyValue >
  </ innerAnyThing >
</anything>

<anything>
  <innerAnyThing>
    <anyValue>replaced3</ anyValue >
  </ innerAnyThing >
  <innerAnyThing>
	<another>
	    <anyValue> replaced3</ anyValue >
	</another>
  </ innerAnyThing >
  <innerAnyThing>
    <anyValue> replaced3</ anyValue >
  </ innerAnyThing >
</anything>


That's why I thought that replacing the string using the XPath string
replace would be the best idea, but I didn't know how to process a node
set as a string and then convert it back to a node set. (Unless there is
a better way to do it.)



Roshan Punnoose
Phone: 301-497-6039

Roshan Punnoose
Phone: 301-497-6039

-----Original Message-----
From: Michael Kay [mailto:mike@xxxxxxxxxxxx]
Sent: Tuesday, January 30, 2007 12:57 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Duplicate Nodes in XSL and transform them

> -A template that takes any node and copies it -Each copy has
> to replace a string "replaceMe" with the string "replaced" +
> i. ( 'i' being the iteration of the copy)

Generally, it's reasonably easy to generate numbers that are computed by
reference to the position of a node in the source tree. In some special
cases you can also use position() to generate a number that reflects the
position in the result tree. But in the general case, this kind of
problem
is best tackled as a two-pass transformation, in which you generate the
numbers in the second pass. For example, rather than inserting a
sequential
number, insert <n/>, and then in the second pass do a "modified copy"
transformation with

<xsl:template match="n">
  <xsl:number level="any"/>
</xsl:template>

(You can do a two-pass transform with two stylesheets, or within a
single
stylesheet, whichever is most convenient. Using two stylesheets is a bit
harder to set up but gives you more reusable code.)

Michael Kay
http://www.saxonica.com/