Subject: Re: Duplicate Nodes in XSL and transform them
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 30 Jan 2007 17:50:59 GMT
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something like this, assuming 3 iterations.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:template match="element/*">
<xsl:variable name="n" select="name()"/>
<xsl:for-each select="(//node())[position()<4]">
<xsl:element name="{$n}">
<value>
<xsl:text>replaced</xsl:text>
<xsl:value-of select="position()"/>
</value>
</xsl:element>
</xsl:for-each>
</xsl:template>
<xsl:template match="element">
<xsl:copy>
<xsl:apply-templates select="*"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
$ saxon repl.xml repl.xsl
<?xml version="1.0" encoding="utf-8"?>
<element>
<innerElement>
<value>replaced1</value>
</innerElement>
<innerElement>
<value>replaced2</value>
</innerElement>
<innerElement>
<value>replaced3</value>
</innerElement>
</element>
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