Re: [xsl] Grouping the elements

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Subject: Re: Grouping the elements
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Thu, 14 Sep 2006 15:25:41 +0200

Mukul Gandhi wrote:


   <xsl:template match="/Root">
        <Root>
            <xsl:for-each select="*[generate-id() =
generate-id(key('x', local-name())[1])]">

Hi Mukul, this was what I was looking for in my solution, but couldn't get right. Humbly updating my solution with yours, gives the following, making it better looking than the original:

<xsl:key name="x" match="Root/*" use="local-name()" />

<xsl:template match="Root">
   <xsl:copy>
       <xsl:apply-templates
        select="*[generate-id() =
           generate-id(key('x', local-name())[1])]"/>
   </xsl:copy>
</xsl:template>

Current Thread
Re: looking for an attribute, (continued) Abel Braaksma - 14 Sep 2006 11:48:05 -0000 Arulraj - 14 Sep 2006 12:02:52 -0000 Abel Braaksma - 14 Sep 2006 12:34:31 -0000 Mukul Gandhi - 14 Sep 2006 12:52:05 -0000 Abel Braaksma - 14 Sep 2006 13:25:52 -0000 <= David Carlisle - 14 Sep 2006 11:53:39 -0000

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Re: Grouping the elements, Mukul Gandhi	Thread	Re: looking for an attribute, David Carlisle
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