Re: Processing IDREFS attributes

then you should be able to say:

  <xsl:for-each select="id(@references)/@id">
    <xsl:if test="position()>1"> </xsl:if>
    <xsl:value-of select="."/>
  </xsl:for-each>

A slight twist on this does what I wanted, which was to go find the element that has the ID:

  <xsl:for-each select="id(@references)/@id">
    <xsl:value-of select="id(.)"/>
  </xsl:for-each>

This produces the content of the element with the assigned ID. Without it, I just got the id value.

<xsl:for-each select="id(@references)">
  <xsl:value-of select="."/>
</xsl:for-each>

With my original code with added context:
<xsl:templete match='foo'>
<xsl:for-each select="id(@references)">
        <xsl:value-of select="."/>
</xsl:for-each>
</xsl:template>

It didn't loop for one problem, so there was only a single output, instead of two values as I expected. The output was just the same value as my @references content.

I can't fathom what is going on and why the @references is just being repeated ... that code should have given you the concatenated string values of the elements whose ID typed attribute has a value in the tokenized set of values of the @reference node.

Cheers,
Wendell

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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                    Direct Phone: 301/315-9635
Suite 207                                          Phone: 301/315-9631
Rockville, MD  20850                                 Fax: 301/315-8285
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