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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Processing IDREFS attributes
At 2005-11-01 13:00 -0800, Dan Vint wrote:
I've got a few places where I have an attribute of type IDREFS and a sequence of ID values like references="Location Party Organization". I had thought a simple for-each loop would pull these apart with the id() function, in something like this: Close .... But it doesn't work. What I get is the content of @references with the above. Really? I would have thought you'd get the concatenation of the element content of the referenced elements. The only other solution I have thought about is creating a template and recursively pulling apart the string. This should work, but I would think there is a simpler way to make this work. Is there a solution I missed? *If* you have properly declared the id attributes, for my example they are called id=, something along the lines of: <!ATTLIST foo id ID #IMPLIED> then you should be able to say: <xsl:for-each select="id(@references)/@id">
<xsl:if test="position()>1"> </xsl:if>
<xsl:value-of select="."/>
</xsl:for-each>and it would report a space-separated list of unique token values (rather than just @references since that might have duplicates). If you don't have a declaration of the attribute type, then id() has nothing to look up and will always return an empty node set. I hope this helps, Dan. . . . . . . . . . Ken -- World-wide on-site corporate, govt. & user group XML/XSL training. G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995) Male Cancer Awareness Aug'05 http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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