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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Need help using variable in select statement
Variables in XPath represent values, they don't (like macro variables in a shell language) represent bits of text to be inserted textually into an expression. To evaluate an XPath expression read at run-time from a source document, use an xx:evaluate() expression if your XSLT processor offers one. This can't be done in pure XSLT without extensions. Namespace prefixes can make it messy even with extensions. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Frank Stoner [mailto:fstoner@xxxxxxx] > Sent: 26 September 2005 15:38 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Need help using variable in select statement > > I'm trying to mimic the functionality of a tag used in > documenting .NET C# code. > The tag identifies a file and path location of xml content to merge > into the source document. > > <include file="content.xml" path="/Top/Child[@name='Me']/*" /> > > The template that I have written to translate this tag is simply: > > <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/ > Transform"> > <xsl:template match="include"> > <xsl:variable name="file" select="@file"/> > <xsl:variable name="path" select="@path"/> > <xsl:copy-of select="document($file)$path"/> > </xsl:template> > </xsl:stylesheet> > > The problem is that the use of the $path variable in the "select=" > statement seems to violate some syntax rule and all I get is a > complaint about an unexpected token on that line. > > Now if I substitute the variable value "Top/Child[@name='Me']/*" in > place of the "$path" variable, the template works as expected. > > I've tried a number of ways to build the select statement, but none > have worked out. Any suggestions? > > Thanks, > Frank
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