Re: following-sibling and xsl:sort
<xsl:apply-templates select="B"> <xsl:sort select="B" order="ascending"/> B doesn't have B children so the sort key is the empty set and so no sort will occur. <xsl:template match="B"> <xsl:if test="not(position()=last())"> Because there is no sorting then on the last B node <xsl:variable name="nextB" select="number(following-sibling::B)"/> following-sibling::B is empty so number is not-a-number (NaN) David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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