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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Transforming XML to XML
Per your suggestion, I have tried both of the following stylesheets: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:template match="/"> <xsl:apply-templates select="Data"/> </xsl:template> <xsl:template match="Data"> <xsl:copy-of select="."/> </xsl:template> </xsl:stylesheet> AND <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:template match="/"> <xsl:copy-of select="Data"/> </xsl:template> </xsl:stylesheet> Both of these stylesheets are still returning just a string from the following XML: <?xml-stylesheet type="text/xsl" href="renewal.xsl"?> <Data> <car>Chevy</car> <car>Dodge</car> <car>Ford</car> </Data> Are the modifications that I made to the example above incorrect? ***************************************************************************** ********************* The contents of this email and any attachments are confidential. It is intended for the named recipient(s) only. If you have received this email in error please notify the system manager or the sender immediately and do not disclose the contents to any one or make copies. ** This email was scanned for viruses, vandals and malicious content ** ***************************************************************************** *********************
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