Re: Transforming XML to XML

You have no template defined to handle the Data node, so it is being
processed by the built-in templates, which results in the text value
of car nodes being output. If you want a copy of the Data node, then
use xsl:copy-of

<xsl:template match="/">
  <xsl:copy-of select="Data"/>
</xsl:template>

or define a template to handle the Data nodes

<xsl:template match="Data">
<!-- do something -->
</xsl:template>


Hope that helps,
Josh

On Wed, 11 Aug 2004 16:39:43 -0400, Pilarski, James
<james_pilarski@xxxxxxxxxxxxxxxx> wrote:
> I have a very simple question about transforming XML to XML.  I have been using XSLT to transform XML to XHTML and displaying the result in Internet Explorer.  I would like to do the same but with XML displayed in the browser.  A search of the archives has not provided a satisfactory solution.  Here is a simplified XML file, testdata.xml:
> 
> <?xml-stylesheet type="text/xsl" href="renewal.xsl"?>
> <Data>
>        <car>Chevy</car>
>        <car>Dodge</car>
>        <car>Ford</car>
> </Data>
> 
> Here is a copy of my XSL file:
> 
> <?xml version="1.0" encoding="ISO-8859-1"?>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/>
> <xsl:template match="/">
>                <xsl:apply-templates select="Data"/>
> </xsl:template>
> </xsl:stylesheet>
> 
> From what I have read and from some of the examples I have seen, I would expect this to return an XML file exactly like the original document (testdata.xml).  Instead it is displaying a string consisting of the text from the <car> elements, without the XML tags: ChevyDodgeFord.  What am I overlooking?
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