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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] node's full content + some modifications in that
 Hello,
I'm new in xslt.
I have an xml such as
<?xml version="1.0" encoding="ISO-8859-1"?>
<?xml-stylesheet type="text/xsl" href="cdcatalog.xsl"?>
<catalog>
<cd>
<artist><b>Eros</b> <tab/> Ramazzotti</artist>
</cd>
</catalog>
I want to write out the full content of the node artist, but also want some
modificiation in that markup:
I wanna write out <b>Eros</b>      Ramazotti. (convert
<tab /> to some non-breaking space)
I figured out that <xsl:copy-of> echo the full content of a node, but in
this case, there is no way to do more modification in it, at least I don't
know how to do it. So my current version writes out <b>Eros</b> <tab/>
Ramazzotti.
Current xsl:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table>
<xsl:for-each select="catalog/cd">
<tr>
<td>
<xsl:copy-of select="artist"/>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
In the artist node, there could be more nodes such as <i> <strike>, or
something totally differrent, and more special tags like <tab/> that I want
to convert to non breaking spaces, or something else.
Can you point me what to do?
Thanks, Thomas
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