Re: How to select a document element from the input xm
Your implementation is read by the xslt processor and when it comes across <xsl:output... it doesnt know that you want it to output <xsl:output... but instead assumes you are declaring the <xsl:output../> element. As you probably already know the <xsl:output element must be a direct child of <xsl:stylesheet...> and cannot be inside of a template or anywhere after the first xsl:template element is declared... The way to accomplish what you are trying to do is to use the <xsl:element name="xsl:output"> and then add the necessary attributes using <xsl:attribute name="method">xml</xsl:attribute> etc...
Hope this helps!
Belkin, Alla wrote:
Hello, I am using a stylesheet for modifications of the input xml file to the different format of the xml file. My output file should have a document element, the same as in the input file. How to copy a document element? I can have input XMLs with different document elements. I tried to do something like this, but it doesn't work:
PURCHASE STYLUS STUDIO ONLINE TODAY!
Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!
Download The World's Best XML IDE!
Accelerate XML development with our award-winning XML IDE - Download a free trial today!
Subscribe in XML format