RE: Some help with xsl transform and filter please

Okay so by your method then this would get me each member of the struct node

<?xml version="1.0" ?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
	<xsl:for-each select="methodResponse/params/param/value/array/data/value/struct/member/value[string='Syndicated']">
		<xsl:for-each select="methodResponse/params/param/value/array/data/value/struct/member">
			<xsl:value-of select="methodResponse/params/param/value/array/data/value/struct/member/name" />
			:
			<xsl:value-of select="methodResponse/params/param/value/array/data/value/struct/member/value/string" />
			;<br />
		</xsl:for-each>
	</xsl:for-each>
</xsl:template>
</xsl:stylesheet>

But do I really have to give the path for each item isnt there a way to say start at this path and go down or up?
-----Original Message-----
From: Josh Canfield <Josh.Canfield@xxxxxxxxxxxx>
Sent: Mar 25, 2004 10:33 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Some help with xsl transform and filter please

Your path is incomplete. 

<xsl:template match="/">
	<xsl:for-each select="struct/member/value[string='Syndicated']">

Your template match is putting your context at the root of the document so your for-each is looking for a "struct" node relative to the root, but there isn't one.

You can fully specify the path like this:
<xsl:for-each select="methodResponse/params/param/value/array/data/value/struct/member/value[string='Syndicated']">

This explicitly tells the xpath processor where to find the nodes.

Josh

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