RE: Some help with xsl transform and filter please
Your path is incomplete. <xsl:template match="/"> <xsl:for-each select="struct/member/value[string='Syndicated']"> Your template match is putting your context at the root of the document so your for-each is looking for a "struct" node relative to the root, but there isn't one. You can fully specify the path like this: <xsl:for-each select="methodResponse/params/param/value/array/data/value/struct/member/value[string='Syndicated']"> This explicitly tells the xpath processor where to find the nodes. Josh -----Original Message----- From: Dylan Barber [mailto:dylan.barber@xxxxxxxxxxxxx] Sent: Thursday, March 25, 2004 9:33 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Some help with xsl transform and filter please Okay hope I am not asking something so basic everyone thinks I am a dunce but i have an xml document that comes from a web service like this <?xml version="1.0" encoding="iso-8859-1" ?> <methodResponse> <params> <param> <value> <array> <data> <value> <struct> <member> <name>feedid</name> <value> <string>2403</string> </value> </member> <member> <name>status</name> <value> <string>Syndicated</string> </value> </member> </struct> </value> </data> </array> </value> </param> </params> </methodResponse> I have tried to transform it with something like this <xsl:template match="/"> <xsl:for-each select="struct/member/value[string='Syndicated']"> <xsl:value-of select="name" /> : <xsl:value-of select="string" /> ;<br /> </xsl:for-each> </xsl:for-each> </xsl:template> but this doesnt seem to work. I am a newbie with this whole thing and really need some guidance on how this whole xsl xml thing goes together. Sorry if I have missed the obvious or broken any rules. Dylan Barber (CIW Professional, A+ Technician, Web Designer, Web Developer) home phone-:- (785) 765-2664 work phone-:- (785) 539-3565 x1034 email-:- dylan.barber@xxxxxxxxxxxxx homesite-:- http://www.codegalaxy.com
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