RE: XML to HTML: How to make decisions based on what h
> This shouldn't matter. position() calculates the position of > the current > node within the current node list, which is the list of nodes selected > using <xsl:apply-templates> or <xsl:for-each>. So long as you > select the > nodes to be included using one of those instructions (and not, for > example, by selected a larger set of nodes and then selecting a subset > using xsl:if or xsl:choose) the position() should be set correctly. Thanks for your answer, Michael. Actually, I'm doing exactly what you describe: I select a larger set of nodes, then selecting a subset with xsl:if. So we're back to the original question: is there any way to alternate the row color given that position() won't help me much? > You can't store anything in XSLT - it's a side-effect-free > language; and > there is no concept of "previous" - it's not a sequential execution > model. Thanks a bunch! None of the books I looked at spelled that out explicitly. At least I'm not chasing a chimera any longer. > That shouldn't be necessary. I can't follow your code below I don't blame you: can't figure out much without seeing the input tree. > should be doing something like: > > <xsl:value-of select="name(element[.//*[conditions]])"/> Can you explain more on this? Should "element" stay as such or be replaced with the real name of the element I'm looking for (which turns out to be "Sequence"). Also, "conditions" need to contain an "xsl:for-each". Is that possible? Many thanks, Constantin Vasiliu XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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