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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: XML to HTML: How to make decisions based on what h
>
> > This shouldn't matter. position() calculates the position of
> > the current
> > node within the current node list, which is the list of
> nodes selected
> > using <xsl:apply-templates> or <xsl:for-each>. So long as you
> > select the
> > nodes to be included using one of those instructions (and not, for
> > example, by selected a larger set of nodes and then
> selecting a subset
> > using xsl:if or xsl:choose) the position() should be set correctly.
>
> Thanks for your answer, Michael. Actually, I'm doing exactly what you
> describe: I select a larger set of nodes, then selecting a
> subset with xsl:if. So we're back to the original question:
> is there any way to alternate the row color given that
> position() won't help me much?
Try to restructure it so you select the subset using xsl:for-each.
Instead of
<xsl:for-each select="x">
<xsl:if test="c">
<tr>
do
<xsl:for-each select="x[c]">
<tr>
>
>
> > should be doing something like:
> >
> > <xsl:value-of select="name(element[.//*[conditions]][1])"/>
>
> Can you explain more on this? Should "element" stay as such
> or be replaced with the real name of the element I'm looking
> for (which turns out to be "Sequence").
This was intended as pseudo-code. Substitute the right things for
"element" and "conditions".
Also, "conditions"
> need to contain an "xsl:for-each". Is that possible?
No, it's not possible, but are you really sure it is necessary?
Michael Kay
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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