Re: looping problem, <xsl: for-each>??

Hi Wendell,
  I used
count(preceding::item[category=current()/category])+1
as you wrote (not preceding-sibling). But it was
generating 1,2,1,2 ..

  I would try the _2 pass solution_ and _node-set
based solution_ as you have explained. 

Regards,
Mukul

--- Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> wrote:
> At 09:12 PM 10/7/2003, you wrote:
> >Hi Wendell,
> >  The syntax <xsl:value-of
>
>select="count(preceding::item[category=current()/category])+1"/>
> >when placed at <!-- ?? --> in my XSL, produces
> >numbering 1,2,1,2 and not 1,2,3,4 !
> 
> Are you sure you're using the preceding:: axis, not
> preceding-sibling?
> 
> >I am also interested to know how the numbering
> >(1,2,3,4 ..) can be produced using
> >- a 2 pass solution
> >- using node-set extension
> 
> The two-pass solution would simply be:
> 
> pass 1: sort and create output
> pass 2: number
> 
> The node-set-extension-based solution would be the
> same, except that pass 1 
> would be bound to a variable, then that variable's
> value (a 
> result-tree-fragment) changed to a node-set (in a
> second variable 
> declaration); then you'd apply templates to that
> node set to get the numbering.
> 
> I'd go into more detail but I'm kinda swamped at the
> moment.... :->
> 
> Cheers,
> Wendell
> 
> 
> 
> 
> 
>
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