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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Replacing double quotes with XSLT [faked-from][sls
Try assigning the apostrophe to a variable, and tne using the variable: <xsl:variable name=APOS>'</xsl:variable> ... "translate(../@OrganizationCode,$APOS,'B'"/> -----Original Message----- From: James Paul To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Sent: 22/09/2003 2:38 PM Subject: RE: Replacing double quotes with XSLT [faked-from][sls] Even when trying to replace with the " with a single character it does not work. Example <xsl:element name = "OrganizationCode"> <xsl:text>"</xsl:text> <xsl:value-of select = "translate(../@OrganizationCode,'\"','B'"/> <xsl:text>"</xsl:text> </xsl:element> -----Original Message----- From: Passin, Tom [mailto:tpassin@xxxxxxxxxxxx] Sent: Monday, September 22, 2003 4:01 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: Replacing double quotes with XSLT [ James Paul] > I'm trying to replace " within a string in XSLT and replace it with "" > but I'm not having any luck. > > Does NOT work > > <xsl:element name = "OrganizationCode"> > <xsl:text>"</xsl:text> > <xsl:value-of select = > "translate(../@OrganizationCode,'\"','\"\"'"/> > <xsl:text>"</xsl:text> > </xsl:element> > > Does NOT work > > <xsl:element name = "OrganizationCode"> > <xsl:text>"</xsl:text> > <xsl:value-of select = > "translate(../@OrganizationCode,'"','""'"/> > <xsl:text>"</xsl:text> > </xsl:element> > > Does anyone have any suggestions ??? > Both methods fail because translate() replaces one character with another single character. You have to write a recursive template - it is not hard. See Dave Pawson's FAQ pages, especially http://www.dpawson.co.uk/xsl/sect2/StringReplace.html Cheers, Tom P XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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