RE: Replacing double quotes with XSLT

Recursive template to do what you need.



<xsl:template name="escapeQuot">
    <xsl:param name="text"/>
    <xsl:choose>
      <xsl:when test="contains($text, '&quot;')">
        <xsl:variable name="bufferBefore" select="substring-before($text,
'&quot;')"/>
        <xsl:variable name="newBuffer" select="substring-after($text,
'&quot;')"/>
        <xsl:value-of select="$bufferBefore"/><xsl:text>\"</xsl:text>
        <xsl:call-template name="escapeQuot">
          <xsl:with-param name="text" select="$newBuffer"/>
        </xsl:call-template>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="$text"/>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>



-----Original Message-----
From: Andreas L. Delmelle [mailto:a_l.delmelle@xxxxxxxxxx] 
Sent: Monday, September 22, 2003 5:43 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Replacing double quotes with XSLT

> -----Original Message-----
> From James Paul
> 
> Even when trying to replace with the " with a single character it does
> not work.
> 
> Example
> 
>  <xsl:element name = "OrganizationCode">
>  	<xsl:text>"</xsl:text>
>  	<xsl:value-of select =
>  "translate(../@OrganizationCode,'\"','B'"/>
>  	<xsl:text>"</xsl:text>
>  </xsl:element>
> 

Question: Is this an *exact* copy of what you put in the stylesheet? 
If so, I see a closing bracket missing... (wild guess)


Greetz,


Andreas Delmelle


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