RE: Accessing node-sets by index with position()

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx 
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of 
> Ryan Sawatzky
> Sent: Tuesday, September 23, 2003 8:13 PM
> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Accessing node-sets by index with position()
> 
> 
(...)
> 
> XSLT snippet -----
> <!-- $set is the node-set containing the two <field> elements -->
> 
> <xsl:for-each select="$set">
>     <xsl:text>Iteration #</xsl:text>
>     <xsl:value-of select="position()"/>
>     <xsl:text> is '</xsl:text>
>     <xsl:value-of select="$set[position()]"/>
>     <xsl:text>'&#10;</xsl:text>
> </xsl:for-each>
> 

This is a strange way of doing this but...

The position() is always refered to the current node set, in this case
$set inside the value-of, so this is the same as get $set that has a
position() :) this is always true. You get 111 because the value-of
always get the first node of a nodeset

Try:
<xsl:for-each select="$set">
  <xsl:variable name="pos" select="position()"/>
  <xsl:text>Iteration #</xsl:text>
  <xsl:value-of select="position()"/>
  <xsl:text> is '</xsl:text>
  <xsl:value-of select="$set[position()=$pos]"/>
  <xsl:text>'&#10;</xsl:text>
</xsl:for-each>

Or even better:
<xsl:for-each select="$set">
  <xsl:text>Iteration #</xsl:text>
  <xsl:value-of select="position()"/>
  <xsl:text> is '</xsl:text>
  <xsl:value-of select="."/>
  <xsl:text>'&#10;</xsl:text>
</xsl:for-each>
 
(...)

Hope this helps

Regards,
Americo Albuquerque


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