RE: Getting the root element.

Be advised though, that doesn't always work ... at least maybe not in the
way you think.  I guess it depends on which "document" root node you need.

If you've constructed xml within a variable, lets say, and then you
apply-templates on that given instance, xpathing--within context--to "/"
will take you to the root of the xml "document" within that given variable.

What I mean by "within context" is operations conducted on/within the
context node.  For example, if you xpath to "/" within a predicate or a
for-each that's is operating on the context node.

To get around this, what I do is pre-load a "this" variable at "global"
scope with "/" ... or, you could do it locally--but, I don't think that
makes sense if you plan to access that path within multiple/separate code
paths.

To illustrate what I'm babbling about:

xml:
<xml/>

xsl:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt">
 
  <xsl:output method="text"/>
	
  <xsl:variable name="this" select="/"/>

  <xsl:template match="/">
  
     <xsl:variable name="my-instance">
        <node/>
     </xsl:variable>
    
     <xsl:apply-templates select="msxsl:node-set($my-instance)/node"/>
    
  </xsl:template>

  <xsl:template match="node">
     context "/" name: <xsl:value-of select="name(/*[1])"/>;
     global "/" name : <xsl:value-of select="name($this/*[1])"/>;
  </xsl:template>
   
</xsl:stylesheet>

Anyhow, this may not be an issue for you.

-Jeff


-----Original Message-----
From: Jarno.Elovirta@xxxxxxxxx [mailto:Jarno.Elovirta@xxxxxxxxx]
Sent: Thursday, July 24, 2003 6:02 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Getting the root element.


Hi,

> Q:
> When deep within the structure (In my case recursing down a 
> branch) what it
> the most elegent way of getting the document root node?

/

Cheers,

Jarno - Covenant: Bullet (Club Version)

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