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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Extracting link information from xml document and
Hi,
> <location> http://someserver.ie</location>.
>
> I want to retrieve the URL information and display it as a
> hyperlink in the browser.
>
> Currently, I can view the URL information but it is not a hyperlink.
>
> I thought of using the following:-
> <xsl:template match="technical/location">
> <a href="http://{@link}"><xsl:value-of select="."/></a>
> </xsl:template>
>
> I will be searching different documents so hardwiring in the
> URL where it says "@link" would not provide a solution for
> me. I think that if I could declare a variable in xsl to
> store the retrieved data and then get at the contents of this
> variable within the <a href...> tag - this would provide a solution.
<a href="{.}">
<xsl:value-of select="."/>
</a>
if the source is as you showed above. If the location of the URL varies, try something like
<a>
<xsl:attribute name="href">
<xsl:choose>
<xsl:when test="...">
...
</xsl:when>
...
</xsl:choose>
</xsl:attribute>
<xsl:value-of select="."/>
</a>
Cheers,
Jarno - Front Line Assembly: Virus (Counterized Mix)
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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