Re: how to get rid of tag names
so instead of <p>p line</p> I just need to have p line
I wasn't totally clear about exactly the output you wanted.
Here is a stylesheet which will get rid of the <p> element for you.
With an <xsl:copy-of> which you had in your code you will copy all descendant nodes, which isn't what you wanted.
Try this stylesheet.
<?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="xml" indent="yes" encoding="UTF-8" /> <xsl:template match="/"> <xsl:apply-templates select="*" /> </xsl:template>
<xsl:template match="*"> <xsl:copy> <xsl:apply-templates select="*" /> </xsl:copy> </xsl:template>
<xsl:template match="p"> <xsl:apply-templates /> </xsl:template>
The <xsl:copy> element copies the elements you want but not any descendants. The <xsl:apply-templates> then processes child nodes. By having a separate template for the <p> element node which has no <xsl:copy> then you get rid of the unwanted <p> element but by using <xsl:apply-templates > you get the child text node that you want.
If you had attributes in the source document then you would need to copy those explicitly.
I hope that helps.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
PURCHASE STYLUS STUDIO ONLINE TODAY!
Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!
Download The World's Best XML IDE!
Accelerate XML development with our award-winning XML IDE - Download a free trial today!
Subscribe in XML format