Re: xsl:if giving me "Invalid type" error

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Subject: Re: xsl:if giving me "Invalid type" error
From: Wendell Piez <wapiez@xxxxxxxxxxxxxxxx>
Date: Tue, 15 Apr 2003 13:53:04 -0400

James,

How have you declared $firstDiv?

If it's not a node set, you'll get the error you refer to (since predicate and step operators can only apply to node sets).

Cheers,
Wendell

At 01:19 PM 4/15/2003, you wrote:

<xsl:if test="$firstDiv[1]/preceding-sibling::*">
 ...
</xsl:if>

only works if $firstDiv[1]/preceding-sibling::*
returns empty. Otherwise, I get a complaint about

XPath error Invalid type in
$firstDiv[1]/preceding-sibling::*

Nothing I can think of seems to fix this. I tried
using boolean($firstDiv[1]/preceding-sibling::*), but
I still get the Invalid type error.

What's going on?

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Wendell Piez                            mailto:wapiez@xxxxxxxxxxxxxxxx
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XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list

Current Thread

xsl:if giving me "Invalid type" error
- James J. Ramsey - Tue, 15 Apr 2003 13:14:50 -0400 (EDT)
  - Michael Kay - Tue, 15 Apr 2003 13:39:34 -0400 (EDT)
  - Wendell Piez - Tue, 15 Apr 2003 13:50:09 -0400 (EDT) <=
    - James J. Ramsey - Tue, 15 Apr 2003 14:51:35 -0400 (EDT)
      - David Carlisle - Tue, 15 Apr 2003 15:11:16 -0400 (EDT)
      - James J. Ramsey - Tue, 15 Apr 2003 15:11:19 -0400 (EDT)
      - Wendell Piez - Tue, 15 Apr 2003 16:12:59 -0400 (EDT)

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RE: xsl:if giving me "Invalid, Michael Kay	Thread	Re: xsl:if giving me "Invalid, James J. Ramsey
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