RE: Calculating a sum of rounded numbers

It's the old problem of getting the sum of a computed expression. Solutions
include:

- creating a temporary tree containing the computed values, then doing sum()
on the nodes in the temporary tree
- writing a recursive template to do the summation
- using the saxon:sum() extension function
- using Dimitre's FXSL library
- using XSLT 2.0 / XPath 2.0

Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Nik Krimm
> Sent: 09 May 2002 21:45
> To: xsl-mulberry
> Subject:  Calculating a sum of rounded numbers
>
>
> I am trying the following output from the XML below:
>
> [output]
> .21
> .09
> .2
> sum: .5
>
> [xml]
> <values>
> <value>.2123</value>
> <value>.0923</value>
> <value>.2012</value>
> </values>
>
> 
> <xsl:for-each select="value">
> 	<xsl:value-of select="format-number((.),'.##')" /><br />
> </xsl:for-each>
> sum: <xsl:value-of select="format-number(sum(//value),'.##)" />
>
> Instead I'm getting the output
>
> [output]
> .21
> .09
> .2
> sum: .51
>
> i.e. a rounding error because the numbers are sumed first and
> then rounded, rather than rounded first and then summed.
>
>
> I tried
> <xsl:value-of
> select="format-number(sum(format-number(//measure),'##')" />
>
> But get an error:
> Argument 1 must return a node-set.
> format-number(-->sum(format-number(//measure),'##')<--)
>
> Can anyone suggest a better way to approach this problem that
> is native xsl (i/e/ without extensions)?
>
>
> TIA
>
> nik
>
>
>
>
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>


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