[xsl] problem in using * as a default parameter in xsl:param

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Subject: problem in using * as a default parameter in xsl:param
From: "=?big5?b?qkwgpGyq5A==?=" <minikittygo@xxxxxxxxxxx>
Date: Mon, 29 Apr 2002 15:39:12 +0000

Hi, can somebody tell how could i set the default value of a parameter to all possible value (i.e. *)

this is what i did:

<xsl:param name="param1" select="*"/>
....
<xsl:for-each select="elementName[childName=$param1]">
<xsl:copy-of select="elementName"/>
</xsl:for-each>
...

however this does not work, can somebody let me know how to do it or achieve similiar outcome?

Many thanks
Regards
Kit


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Current Thread
problem in using * as a default parameter in xsl:param =?big5?b?qkwgpGyq5A==?= - Mon, 29 Apr 2002 11:33:54 -0400 (EDT) <= Oleg Tkachenko - Mon, 29 Apr 2002 11:55:45 -0400 (EDT) Michael Kay - Mon, 29 Apr 2002 12:01:51 -0400 (EDT) <Possible follow-ups> TSchutzerWeissmann - Mon, 29 Apr 2002 12:17:42 -0400 (EDT) Oleg Tkachenko - Mon, 29 Apr 2002 13:20:20 -0400 (EDT)

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