RE: problem in using * as a default parameter in xsl:p
Michael Kay wrote: ><xsl:param name="childElement" select="'*'"/> > ><xsl:for-each > select="element[$childElement!='*][childName=$childElement] | > element[$childElement='*']"> > Michael, Oleg, This is an elegant way of making * into a wildcard, but won't it test the text value of the children rather than their name? If one was to use this, select="element/*[local-name()=$childElement]", as Oleg suggests, will * then act as a wildcard anyway? Thanks for your help, Tom XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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