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RE: problem in using * as a default parameter in xsl:p

Subject: RE: problem in using * as a default parameter in xsl:param
From: TSchutzerWeissmann@xxxxxxxxxxxxxxxx
Date: Mon, 29 Apr 2002 17:17:56 +0100
xsl wildcard parameter
Michael Kay wrote:

><xsl:param name="childElement" select="'*'"/>
>   select="element[$childElement!='*][childName=$childElement] |
>           element[$childElement='*']">

Michael, Oleg,

This is an elegant way of making * into a wildcard, but won't it test the
text value of the children rather than their name?

If one was to use this, 
	select="element/*[local-name()=$childElement]", as Oleg suggests,
will * then act as a wildcard anyway?

Thanks for your help,

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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