RE: document() and xpath

Thank you all who replied. 

Meltem

-----Original Message-----
From: Joerg Heinicke [mailto:joerg.heinicke@xxxxxx]
Sent: 29 April 2002 20:15
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  document() and xpath


You have to bring the focus back to the original document. For this you 
must store the document in a variable:

<xsl:variable name="document1" select="/"/>
<xsl:variable name="document2" select="document('xml.xml')"/>

<xsl:for-each select="$document2/menu/name">
   <xsl:apply-templates select="$document1/page/form"/>
</xsl:for-each>

Regards,

Joerg

Meltem Kogelbauer schrieb:
> Hi All,
> 
> here is the simplified version of code;
> 1st XML that is generated on-the-fly
> <page>
> 	<form>
> 		<name/>
> 		<id/>
> 	</form>
> ...
> </page>
> 
> 2nd XML that is a flat file, xml.xml
> <menu>
> 	<name/>
> 	<name/>
> 	<name/>
> </menu>
> 
> In the XSL
> 
> <for-each select="document('xml.xml')/menu/name">
> 	<value-of select="text()"/>
> 	<apply-templates select="/page/form" />
> </for-each>
> 
> 
> My problem is with the xpath (I think) in <apply-templates> element. When
> looping in the external XML, how can I write the XPath to the current
> document? Is this possible?
> 
> cheers
> 
> Meltem


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