Subject: Re: document() and xpath
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Date: Mon, 29 Apr 2002 21:15:13 +0200
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You have to bring the focus back to the original document. For this you
must store the document in a variable:
<xsl:variable name="document1" select="/"/>
<xsl:variable name="document2" select="document('xml.xml')"/>
<xsl:for-each select="$document2/menu/name">
<xsl:apply-templates select="$document1/page/form"/>
</xsl:for-each>
Regards,
Joerg
Meltem Kogelbauer schrieb:
Hi All,
here is the simplified version of code;
1st XML that is generated on-the-fly
<page>
<form>
<name/>
<id/>
</form>
...
</page>
2nd XML that is a flat file, xml.xml
<menu>
<name/>
<name/>
<name/>
</menu>
In the XSL
<for-each select="document('xml.xml')/menu/name">
<value-of select="text()"/>
<apply-templates select="/page/form" />
</for-each>
My problem is with the xpath (I think) in <apply-templates> element. When
looping in the external XML, how can I write the XPath to the current
document? Is this possible?
cheers
Meltem
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